Getting the keyword arguments actually passed to a Python method

Question

I\'m dreaming of a Python method with explicit keyword args:

def func(a=None, b=None, c=None):
    for arg, val in magic_arg_dict.items():   # Where do I get         


        

Answer 1

How about using a decorator to validate the incoming kwargs?

def validate_kwargs(*keys):
    def entangle(f):
        def inner(*args, **kwargs):
            for key in kwargs:
                if not key in keys:
                    raise ValueError("Received bad kwarg: '%s', expected: %s" % (key, keys))
            return f(*args, **kwargs)
        return inner
    return entangle

###

@validate_kwargs('a', 'b', 'c')
def func(**kwargs):
   for arg,val in kwargs.items():
       print arg, "->", val

func(b=2)
print '----'
func(a=3, c=5)
print '----'
func(d='not gonna work')

Gives this output:

b -> 2
----
a -> 3
c -> 5
----
Traceback (most recent call last):
  File "kwargs.py", line 20, in 
    func(d='not gonna work')
  File "kwargs.py", line 6, in inner
    raise ValueError("Received bad kwarg: '%s', expected: %s" % (key, keys))
ValueError: Received bad kwarg: 'd', expected: ('a', 'b', 'c')