How to set/unset a bit at specific position of a long?

Question

How to set/unset a bit at specific position of a long in Java ?

For example,

long l = 0b001100L ; // bit representation

I want to s

Answer 1

The least significant bit (lsb) is usually referred to as bit 0, so your 'position 2' is really 'bit 1'.

long x = 0b001100;  // x now = 0b001100
x |= (1<<1);        // x now = 0b001110 (bit 1 set)
x &= ~(1<<2);       // x now = 0b001010 (bit 2 cleared)