pythonic way to convert variable to list

Question

I have a function whose input argument can either be an element or a list of elements. If this argument is a single element then I put it in a list so I can iterate over the

Answer 1

Typically, strings (plain and unicode) are the only iterables that you want to nevertheless consider as "single elements" -- the basestring builtin exists SPECIFICALLY to let you test for either kind of strings with isinstance, so it's very UN-grotty for that special case;-).

So my suggested approach for the most general case is:

  if isinstance(input, basestring): input = [input]
  else:
    try: iter(input)
    except TypeError: input = [input]
    else: input = list(input)

This is THE way to treat EVERY iterable EXCEPT strings as a list directly, strings and numbers and other non-iterables as scalars (to be normalized into single-item lists).

I'm explicitly making a list out of every kind of iterable so you KNOW you can further on perform EVERY kind of list trick - sorting, iterating more than once, adding or removing items to facilitate iteration, etc, all without altering the ACTUAL input list (if list indeed it was;-). If all you need is a single plain for loop then that last step is unnecessary (and indeed unhelpful if e.g. input is a huge open file) and I'd suggest an auxiliary generator instead:

def justLoopOn(input):
  if isinstance(input, basestring):
    yield input
  else:
    try:
      for item in input:
        yield item
    except TypeError:
      yield input

now in every single one of your functions needing such argument normalization, you just use:

 for item in justLoopOn(input):

You can use an auxiliary normalizing-function even in the other case (where you need a real list for further nefarious purposes); actually, in such (rarer) cases, you can just do:

 thelistforme = list(justLoopOn(input))

so that the (inevitably) somewhat-hairy normalization logic is just in ONE place, just as it should be!-)