Virtual Table C++

Question

I read a lot of people writing \"a virtual table exists for a class that has a virtual function declared in it\".

My question is, does a vtable exists only for a cla

Answer 1

Yes it's true. Actually, given base's defintion:

class derived:public base{
public:
 void print(){cout<<"derived print\n";}
};

is completely equivalent to:

class derived:public base{
public:
 virtual void print(){cout<<"derived print\n";}
};

... because you already defined print as virtual in base.

I'd wish the compiler would enforce that...