Binding a class to an interface

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伪装坚强ぢ
伪装坚强ぢ 2020-12-24 01:55

Using typescript, I can easily bind classes to themselves:

bootstrap(MyAppComponent, [MyClass]);

However, I would like to bind my class to

2条回答
  •  既然无缘
    2020-12-24 02:39

    I dont know if it is possible with interface as interface will not be available at runtime (javascript does not know about interface). But it can be done using abstract classes.

    //abstract-parent-service.ts

    export class DatabaseService{
        getService: ()=>string;
    }
    

    //hibernate.service.ts

    import {DatabaseService} from "./abstract-parent-service";
    
    export class HibernateService implements DatabaseService{
      constructor() { }
      getService() {
        return "i am hibernate";
      }
    }
    

    //jdbc.service.ts

    import {DatabaseService} from "./abstract-parent-service";
    
    export class JDBCService implements DatabaseService{
      constructor() { }
      getService() {
        return "i am Jdbc";
      }
    }
    

    //cmp-a.component.ts

    import {DatabaseService} from "./abstract-parent-service";
    import {HibernateService} from "./hibernate.service";
    
    @Component({
        selector: 'cmp-a',
        template: `

    Hello Hibernate

    `, providers: [{provide: DatabaseService, useClass: HibernateService}] }) export class CmpAComponent { constructor (private databaseService: DatabaseService) { console.log("Database implementation in CompA :"+this.databaseService.getService()); } }

    //cmp-b.component.ts

    import {DatabaseService} from "./abstract-parent-service";
    import {HibernateService} from "./hibernate.service";
    
    @Component({
        selector: 'cmp-b',
        template: `

    Hello Jdbc

    `, providers: [{provide: DatabaseService, useClass: JDBCService}] }) export class CmpAComponent { constructor (private databaseService: DatabaseService) { console.log("Database implementation in CompA :"+this.databaseService.getService()); } }

    But the problem with this implementation is HibernateService and JDBCService are not able to extend any other class now because they have already got married with DatabaseService.

    class A{
        constructor(){
            console.log("in A");
        }
    }
    class B extends A{
        constructor(){
            super();
            console.log("in B");
        }
    }
    class C extends A{
        constructor(){
            super();
            console.log("in C");
        }
    }
    let c = new C();
    
    //This thing is not possible in typescript
    class D extends B, C{//error:  Classes can only extend a single class
        constructor(){
            super();// which constructor B or C
            console.log("in D");
        }
    }
    

    If you are using this pattern for DI, make it sure that your child class services are not going to extend any other functionality in future.

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