Test a specific exception type is thrown AND the exception has the right properties

Question

I want to test that MyException is thrown in a certain case. EXPECT_THROW is good here. But I also want to check the exception has a specific state

Answer 1

I recommend defining a new macro based on Mike Kinghan's approach.

#define ASSERT_EXCEPTION( TRY_BLOCK, EXCEPTION_TYPE, MESSAGE )        \
try                                                                   \
{                                                                     \
    TRY_BLOCK                                                         \
    FAIL() << "exception '" << MESSAGE << "' not thrown at all!";     \
}                                                                     \
catch( const EXCEPTION_TYPE& e )                                      \
{                                                                     \
    EXPECT_EQ( MESSAGE, e.what() )                                    \
        << " exception message is incorrect. Expected the following " \
           "message:\n\n"                                             \
        << MESSAGE << "\n";                                           \
}                                                                     \
catch( ... )                                                          \
{                                                                     \
    FAIL() << "exception '" << MESSAGE                                \
           << "' not thrown with expected type '" << #EXCEPTION_TYPE  \
           << "'!";                                                   \
}

Mike's TEST(foo_test,out_of_range) example would then be

TEST(foo_test,out_of_range)
{
    foo f;
    ASSERT_EXCEPTION( { f.bar(111); }, std::out_of_range, "Out of range" );
}

which I think ends up being much more readable.