How to start multiple processes in Bash

Question

I want to start 100 processes in bash, but the for statement doesn\'t seems to like the & symbol and I\'m getting a syntax error,

Answer 1

With GNU Parallel you can do:

echo "Spawning 100 processes"
parallel -j0 ./my_script.py ::: {1..100}

Or to avoid the argument 1 through 100:

parallel -j0 -N0 ./my_script.py ::: {1..100}

Without -j0 it will spawn one process per CPU thread.

Watch the intro videos for more details: https://www.youtube.com/playlist?list=PL284C9FF2488BC6D1