success_url in UpdateView, based on passed value

Question

How can I set success_url based on a parameter?
I really want to go back to where I came from, not some static place. In pseudo code:

url(r         


        

Answer 1

I found a way which is useful and very simple. Check it out.

class EmployerUpdateView(UpdateView):
        model = Employer
        #other stuff.... to be specified

        def get_success_url(self):
           pk = self.kwargs["pk"]
           return reverse("view-employer", kwargs={"pk": pk})