success_url in UpdateView, based on passed value

Question

How can I set success_url based on a parameter?
I really want to go back to where I came from, not some static place. In pseudo code:

url(r         


        

Answer 1

Create a class MyUpdateView inheritted from UpdateView and override get_success_url method:

class MyUpdateView(UpdateView):
    def get_success_url(self):
        pass #return the appropriate success url

Also i like to pass such parameters like template_name and model inside of inheritted class view, but not in .as_view() in urls.py