Defining an object without calling its constructor in C++

Question

In C++, I want to define an object as a member of a class like this:

Object myObject;

However doing this will try to call it\'s parameterle

Answer 1

You can fully control the object construction and destruction by this trick:

template
struct DefferedObject
{
    DefferedObject(){}
    ~DefferedObject(){ value.~T(); }
    template
    void Construct(TArgs&&...args)
    {
        new (&value) T(std::forward(args)...);
    }
public:
    union
    {
        T value;
    };
};

Apply on your sample:

class Program
{
public:
   DefferedObject