This question is similar to this question about subtracting dates with Python, but not identical. I\'m not dealing with strings, I have to figure out the difference between
def humanize_time(amount, units = 'seconds'):
def process_time(amount, units):
INTERVALS = [ 1, 60,
60*60,
60*60*24,
60*60*24*7,
60*60*24*7*4,
60*60*24*7*4*12,
60*60*24*7*4*12*100,
60*60*24*7*4*12*100*10]
NAMES = [('second', 'seconds'),
('minute', 'minutes'),
('hour', 'hours'),
('day', 'days'),
('week', 'weeks'),
('month', 'months'),
('year', 'years'),
('century', 'centuries'),
('millennium', 'millennia')]
result = []
unit = map(lambda a: a[1], NAMES).index(units)
# Convert to seconds
amount = amount * INTERVALS[unit]
for i in range(len(NAMES)-1, -1, -1):
a = amount // INTERVALS[i]
if a > 0:
result.append( (a, NAMES[i][1 % a]) )
amount -= a * INTERVALS[i]
return result
rd = process_time(int(amount), units)
cont = 0
for u in rd:
if u[0] > 0:
cont += 1
buf = ''
i = 0
for u in rd:
if u[0] > 0:
buf += "%d %s" % (u[0], u[1])
cont -= 1
if i < (len(rd)-1):
if cont > 1:
buf += ", "
else:
buf += " and "
i += 1
return buf
Example of use:
>>> print humanize_time(234567890 - 123456789)
3 years, 9 months, 3 weeks, 5 days, 11 minutes and 41 seconds
>>> humanize_time(9, 'weeks')
2 months and 1 week
Advantage (You don't need third parties!).
Improved from "Liudmil Mitev" algorithm. (Thanks!)