Using Hashmap (O(n^2) solution):
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import static java.lang.Math.pow;
/**
* Created by Anup on 10-10-2016.
*/
class Pair {
int a;
int b;
Pair(int x, int y) {
a = x;
b = y;
}
}
public class FindCubePair {
public static void main(String[] args) {
HashMap> hashMap = new HashMap<>();
int n = 100000;
for(int i = 1; i <= n; i++) {
for(int j = 1; j <= n; j++) {
long sum = (long) (pow(i, 3) + pow(j, 3));
if(hashMap.containsKey(sum)) {
List list = hashMap.get(sum);
for(Pair p : list) {
System.out.println(i + " " + j + " " + p.a + " " + p.b);
}
} else {
ArrayList list = new ArrayList<>();
hashMap.put(sum, list);
}
hashMap.get(sum).add(new Pair(i, j));
}
}
}
}
Unfortunately, the value of integers printed does not even reach 1000 on my computer due to resource limitation.