C++ typedef member function signature syntax

Question

I want to declare type definition for a member function signature. Global function typedefs look like this:

typedef int (function_signature)(int, int);
typed         


        

Answer 1

It works for me:

#include 

class foo
  {
public:
  int g (int x, int y) { return x + y ; }
  } ;

typedef int (foo::*memberf_pointer)(int, int);

int main()
  {
  foo f ;
  memberf_pointer mp = &foo::g ;
  std::cout << (f.*mp) (5, 8) << std::endl ;
  }