Create a List that contain each Line of a File

Question

I\'m trying to open a file and create a list with each line read from the file.

   i=0
   List=[\"\"]
   for Line in inFile:
      List[i]=Line.split(\",\")
         


        

Answer 1

A file is almost a list of lines. You can trivially use it in a for loop.

myFile= open( "SomeFile.txt", "r" )
for x in myFile:
    print x
myFile.close()

Or, if you want an actual list of lines, simply create a list from the file.

myFile= open( "SomeFile.txt", "r" )
myLines = list( myFile )
myFile.close()
print len(myLines), myLines

You can't do someList[i] to put a new item at the end of a list. You must do someList.append(i).

Also, never start a simple variable name with an uppercase letter. List confuses folks who know Python.

Also, never use a built-in name as a variable. list is an existing data type, and using it as a variable confuses folks who know Python.