Create a List that contain each Line of a File

Question

I\'m trying to open a file and create a list with each line read from the file.

   i=0
   List=[\"\"]
   for Line in inFile:
      List[i]=Line.split(\",\")
         


        

Answer 1

Please read PEP8. You're swaying pretty far from python conventions.

If you want a list of lists of each line split by comma, I'd do this:

l = []
for line in in_file:
    l.append(line.split(','))

You'll get a newline on each record. If you don't want that:

l = []
for line in in_file:
    l.append(line.rstrip().split(','))