How do I get the day month and year from a Windows cmd.exe script?

Question

How do I get the current day month and year from inside a Windows cmd script? I need to get each value into a separate variable.

Answer 1

For one line!

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Try using for wmic OS Get localdatetime^|find "." in for /f without tokens and/or delims, this works in any language / region and also, no user settings interfere with the layout of the output.

• In command line:

for /f %i in ('wmic OS Get localdatetime^|find "."')do @cmd/v/c "set _date=%i &echo= year: !_date:~0,4!&&echo=month:   !_date:~4,2!&echo=  day:   !_date:~6,2!"

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• In bat/cmd file:

for /f %%i in ('wmic OS Get localdatetime^|find "."')do @cmd/v/c "set _date=%%i &echo= year: !_date:~0,4!&&echo=month:   !_date:~4,2!&echo=  day:   !_date:~6,2!"

Results:

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 year: 2019
month:   06
  day:   12

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• With Hour and Minute in bat/cmd file:

for /f %%i in ('wmic OS Get localdatetime^|find "."')do @cmd/v/c "set _date=%%i &echo=  year: !_date:~0,4!&&echo= month:   !_date:~4,2!&echo=   day:   !_date:~6,2!&echo=  hour:   !_date:~8,2!&echo=minute:   !_date:~10,2!"

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• With Hour and Minute in command line:

for /f %i in ('wmic OS Get localdatetime^|find "."')do @cmd/v/c "set _date=%i &echo=  year: !_date:~0,4!&&echo= month:   !_date:~4,2!&echo=   day:   !_date:~6,2!&echo=  hour:   !_date:~8,2!&echo=minute:   !_date:~10,2!"

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Results:

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  year: 2020
 month:   05
   day:   16
  hour:   00
minute:   46