How do I get the day month and year from a Windows cmd.exe script?

Question

How do I get the current day month and year from inside a Windows cmd script? I need to get each value into a separate variable.

Answer 1

I think that Andrei Coscodan answer is the best when you can't make many assumptions. But sometimes having a one-liner is nice if you can make some some assumptions. This solution assumes that 'date \t' will return one of two formats. On WindowsXP 'date /t 'returns "11/23/2011", but on Windows7 it returns "Wed 11/23/2011".

FOR /f "tokens=1-4 delims=/ " %%a in ('date /t') do (set mm=%%a&set dd=%%b&set yyyy=%%c& (if "%%a:~0,1" gtr "9" set mm=%%b&setdd=%%c&set yyyy=%%d))
:: Test results
echo day in 'DD' format is '%dd%'; month in 'MM' format is '%mm%'; year in 'YYYY' format is '%yyyy%'

Thanks to Andrei Consodan answer to help me with this one-line solution.