output of numpy.where(condition) is not an array, but a tuple of arrays: why?

Question

I am experimenting with the numpy.where(condition[, x, y]) function.
From the numpy documentation, I learn that if you give just one array as input, it shou

Answer 1

Just use np.asarray function. In your case:

>>> import numpy as np
>>> array = np.array([1,2,3,4,5,6,7,8,9])
>>> pippo = np.asarray(np.where(array>4))
>>> pippo + 1
array([[5, 6, 7, 8, 9]])