Is there a fast way to generate a dict of the alphabet in Python?

Question

I want to generate a dict with the letters of the alphabet as the keys, something like

letter_count = {\'a\': 0, \'b\': 0, \'c\': 0}

what

Answer 1

You can use dictionary and range directly, so you can create your own function and easily customize it.

def gen_alphabet(start, value):
    return {chr(ord('a') + i) : 0 for i in range(value)}

print(gen_alphabet('a', 26))

OUTPUT:

>>> {'a': 0, 'c': 0, 'b': 0, 'e': 0, 'd': 0, 'g': 0, 'f': 0, 'i': 0, 'h': 0, 'k': 0, 'j': 0, 'm': 0, 'l': 0, 'o': 0, 'n': 0, 'q': 0, 'p': 0, 's': 0, 'r': 0, 'u': 0, 't': 0, 'w': 0, 'v': 0, 'y': 0, 'x': 0, 'z': 0}