How to minify ES6 functions with gulp-uglify?

Question

When I run gulp I get the following error:

[12:54:14] { [GulpUglifyError: unable to minify JavaScript]
cause:
{ [SyntaxError: Unexpected token: operator (>         


        

Answer 1

You actually can uglify ES6 code without transpilation. Instead of gulp-uglify plugin, use gulp-uglifyes plugin.

var gulp = require('gulp');
var rename = require('gulp-rename'); 
var uglify = require('gulp-uglifyes');
var plumber = require('gulp-plumber');
var plumberNotifier = require('gulp-plumber-notifier');
var sourcemaps = require('gulp-sourcemaps');
var runSequence = require('run-sequence').use(gulp);

gulp.task('minjs', function () {
  return gulp.src(['/dist/**/*.js', '!/dist/**/*.min.js'])
    .pipe(plumberNotifier())
    .pipe(sourcemaps.init())
    .pipe(uglify({ 
       mangle: false, 
       ecma: 6 
    }))
    .pipe(rename(function (path) {
      path.extname = '.min.js';
    }))
    .pipe(sourcemaps.write('.'))
    .pipe(gulp.dest('/dist'));
});