Is it possible to do computation before super() in the constructor?

Question

Given that I have a class Base that has a single argument constructor with a TextBox object as it\'s argument. If I have a class Simple of the following form:

Answer 1

It is required by the language in order to ensure that the superclass is reliably constructed first. In particular, "If a constructor does not explicitly invoke a superclass constructor, the Java compiler automatically inserts a call to the no-argument constructor of the superclass."

In your example, the superclass may rely on the state of t at construction time. You can always ask for a copy later.

There's an extensive discussion here and here.