Given an input array we can find a single sub-array which sums to K (given) in linear time, by keeping track of sum found so far and the start position. If the current sum b
Try this code this can work for you:
private static void printSubArrayOfRequiredSum(int[] array, int requiredSum) {
for (int i = 0; i < array.length; i++) {
String str = "[ ";
int sum = 0;
for (int j = i; j < array.length; j++) {
sum = sum + array[j];
str = str + array[j] + ", ";
if (sum == requiredSum) {
System.out.println(" sum : " + sum + " array : " + str
+ "]");
str = "[ ";
sum = 0;
}
}
}
}
Use this method like :
int array[] = { 3, 5, 6, 9, 14, 8, 2, 12, 7, 7 };
printSubArrayOfRequiredSum(array, 14);
Output :
sum : 14 array : [ 3, 5, 6, ]
sum : 14 array : [ 14, ]
sum : 14 array : [ 2, 12, ]
sum : 14 array : [ 7, 7, ]