If a is the array, I want a.index(a.max), but something more Ruby-like. It should be obvious, but I\'m having trouble finding the answer at so and
Just wanted to note a behavioral and performance difference for some of the solutions here. The "tie breaking" behavior of duplicate max elements:
a = [3,1,2,3]
a.each_with_index.max[1]
# => 3
a.index(a.max)
# => 0
Out of curiosity I ran them both in Benchmark.bm (for the a above):
user system total real
each_with_index.max 0.000000 0.000000 0.000000 ( 0.000011)
index.max 0.000000 0.000000 0.000000 ( 0.000003)
Then I generated a new a with Array.new(10_000_000) { Random.rand } and reran the test:
user system total real
each_with_index.max
2.790000 0.000000 2.790000 ( 2.792399)
index.max 0.470000 0.000000 0.470000 ( 0.467348)
This makes me think unless you specifically need to choose the higher index max, a.index(a.max) is the better choice.