How to print all the columns after a particular number using awk?

Question

On shell, I pipe to awk when I need a particular column.

This prints column 9, for example:

... | awk \'{print $9}\'

How can I tell

Answer 1

function print_fields(field_num1, field_num2){
    input_line = $0

    j = 1;
    for (i=field_num1; i <= field_num2; i++){
        $(j++) = $(i);

    }
    NF = field_num2 - field_num1 + 1;
    print $0

    $0 = input_line
}