How to print all the columns after a particular number using awk?

Question

On shell, I pipe to awk when I need a particular column.

This prints column 9, for example:

... | awk \'{print $9}\'

How can I tell

Answer 1

awk '{print substr($0, index($0,$9))}'

Edit: Note, this doesn't work if any field before the ninth contains the same value as the ninth.