Using sed, how do you print the first 'N' characters of a line?

Question

Using sed what is an one liner to print the first n characters? I am doing the following:

grep -G \'defn -test.*\' OctaneFullTest.clj          


        

Answer 1

Don't use sed, use cut:

grep .... | cut -c 1-N

If you MUST use sed:

grep ... | sed -e 's/^\(.\{12\}\).*/\1/'