I recently came across an interview question asked by Amazon and I am not able to find an optimized algorithm to solve this question:
You are given an input array wh
I have a solution that only requires a single traversal from left to right.
def standing_water(heights):
if len(heights) < 3:
return 0
i = 0 # index used to iterate from left to right
w = 0 # accumulator for the total amount of water
while i < len(heights) - 1:
target = i + 1
for j in range(i + 1, len(heights)):
if heights[j] >= heights[i]:
target = j
break
if heights[j] > heights[target]:
target = j
if target == i:
return w
surface = min(heights[i], heights[target])
i += 1
while i < target:
w += surface - heights[i]
i += 1
return w