Size of array object passed to function

Question

I am running the following code in C++:

class Tile {
    //class definition
};

bool myFunction(Tile* Tiles) {
    sizeof(Tiles);
    sizeof(Tiles[0]);
    /         


        

Answer 1

The simplest, C-sytle way is to pass the array size as a parameter.

bool myFunction_ver1(Tile* Tiles, std::size_t size)
{
    //...
}

But C++ offers more. Since array size is contained in the data type of the array, a template can help. The array should be passed by reference to prevent the array from being adjusted to pointer.

template 
bool myFunction_ver2(const Tile (&Tiles)[N])
{
    // N is the array size
}

But we should prefer using std::array or std::vector instead of raw array.

template 
bool myFunction_ver3(const std::array& Tiles)
{
    // You may use N or Tiles.size()
}

bool myFunction_ver4(const std::vector& Tiles)
{
    // use Tiles.size()
}