How to get request URI without context path?

Question

The Method request.getRequestURI() returns URI with context path.

For example, if the base URL of an application is http://localhost:8080/myapp/ (i.e.

Answer 1

May be you can just use the split method to eliminate the '/myapp' for example:

string[] uris=request.getRequestURI().split("/");
string uri="/"+uri[1]+"/"+uris[2];