C implementention of strcpy does not change variable value [duplicate]

Answer 1

You don't need the & to reference the char * because it is already a pointer to a character, you don't want char ** which is a pointer to a pointer to a character.

I patched it up:

void my_strcpy(char** dest, const char* src) {
    const char * srcTemp = src;
    int i = 1; //+1 for null char
    while (*srcTemp != '\0') {
        srcTemp++;
        i++;
    }
    char * destTemp = (char*)malloc(sizeof(char)*i);
    *dest = destTemp;

    while (*src != '\0') {
        *destTemp = *src;
        src++;
        *destTemp++;
    }
    *destTemp = *src; //copy null char

}

int _tmain(int argc, _TCHAR* argv[])
{
    const char* s = "Hello World";
    char* test = 0;

    my_strcpy(&test, s); // Suposed to change test form d to Hello World.
    printf("Changed String: ");
    printf("%s", test);


    return 0;
}