You are given an unsorted array of n integers, and you would like to find if there are any duplicates in the array (i.e. any integer appearing more than once). D
A variance of Bucket Sort will do. This will give you complexity of O(n) where 'n' is the number of input elements.
But one restriction - max value. You should know the max value your integer array can take. Lets say it as m.
The idea is to create a bool array of size m (all initialized to false). Then iterate over your array. As you find an element, set bucket[m] to true. If it is already true then you've encountered a duplicate.
A java code,
// alternatively, you can iterate over the array to find the maxVal which again is O(n).
public boolean findDup(int [] arr, int maxVal)
{
// java by default assigns false to all the values.
boolean bucket[] = new boolean[maxVal];
for (int elem : arr)
{
if (bucket[elem])
{
return true; // a duplicate found
}
bucket[elem] = true;
}
return false;
}
But the constraint here is the space. You need O(maxVal) space.