count of zeros between the 1st and 14th digit by using grep [closed]

Answer 1

A (mostly) Bash solution using shell parameter expansion to get the first 14 characters:

file='500000000000922801808800000000000000000000922891863600000GS5'
count=$(echo "${file:0:13}" | grep --fixed-strings --only-matching 0 | wc -l)
if [[ $count -ne 12 ]]; then 
    mv "$file" "$drp_dir"
else
    mv "$file" "$dst_dir"
fi

You might also use head -c instead if you prefer.