I need to convert from two\'s complement to sign-magnitude in C using only the operators
! ~ & ^ | + << >>
My approach is t
To get the last bit you could use mask operation
int last_bit = 32 bit integer & 0x80000000
o/p may be 0 or 0x80000000
if it is 0 just display the given number else you have to perform the following operations to represent in signed magnitude
1) Subtract 1 from the number
2) perform 1s complement on the resultant ( that is negation ~)
3) Set the last bit of the resultant number
I mean ( ~ (num -`1) ) | 0x7fffffff
since your restricted not to use - operator. Perform the 2's complement on -1 and add it to the num.
To put it simple in one line
num & 0x80000000 ? printf("%d",(~(num+((~1)+1))) | 0x7fffffff) : printf("%d",num) ;