How can I split a text file into multiple text files using python?

Question

I have a text file that contains the following contents. I want to split this file into multiple files (1.txt, 2.txt, 3.txt...). Each a new output file will be as the follow

Answer 1

try re.findall() function:

import re

with open('input.txt', 'r') as f:
    data = f.read()

found = re.findall(r'\n*(A.*?\n\$\$)\n*', data, re.M | re.S)

[open(str(i)+'.txt', 'w').write(found[i-1]) for i in range(1, len(found)+1)]

Minimalistic approach for the first 3 occurrences:

import re

found = re.findall(r'\n*(A.*?\n\$\$)\n*', open('input.txt', 'r').read(), re.M | re.S)

[open(str(found.index(f)+1)+'.txt', 'w').write(f) for f in found[:3]]

Some explanations:

found = re.findall(r'\n*(A.*?\n\$\$)\n*', data, re.M | re.S)

will find all occurrences matching the specified RegEx and will put them into the list, called found

[open(str(found.index(f)+1)+'.txt', 'w').write(f) for f in found]

iterate (using list comprehensions) through all elements belonging to found list and for each element create text file (which is called like "index of the element + 1.txt") and write that element (occurrence) to that file.

Another version, without RegEx's:

blocks_to_read = 3
blk_begin = 'A'
blk_end = '$$'

with open('35916503.txt', 'r') as f:
    fn = 1
    data = []
    write_block = False
    for line in f:
        if fn > blocks_to_read:
            break 
        line = line.strip()
        if line == blk_begin:
            write_block = True
        if write_block:
            data.append(line)
        if line == blk_end:
            write_block = False
            with open(str(fn) + '.txt', 'w') as fout:
                fout.write('\n'.join(data))
                data = []
            fn += 1

PS i, personally, don't like this version and i would use the one using RegEx