How to replace Strings in Windows Batch file

Question

I would like to replace the following String in a file:

android:versionName=\"anyStringHere\" >

*anyStringHere represents any possible s

Answer 1

Not even close to the fastest option, and not 100% bulletproof, but this is pure batch and will handle spacing and indentation while do the replacement.

@echo off
    setlocal enableextensions disabledelayedexpansion

    rem File to process
    set "file=data.txt"

    rem How to find lines
    set "match=public static String CONST = \"abc\";"

    rem String to replace and replacement
    set "findStr=abc"
    set "replaceStr=def"

    rem temporary file to work with lines
    set "tempFile=%temp%\repl.tmp"

    rem All the output goes into the temporary file
    (

        rem Process input file extracting non matching lines
        for /f tokens^=^1^*^ delims^=^:^ eol^= %%a in ('findstr /n /v /c:"%match%" ^< "%file%"') do (
            set /a "n=1000000+%%a" 
            setlocal enabledelayedexpansion
            < nul set /p "n=!n!"
            endlocal
            echo :%%b
        )

        rem Process input file extrancting matching lines and changing strings
        for /f tokens^=^1^*^ delims^=^:^ eol^= %%a in ('findstr /n /c:"%match%" ^< "%file%"') do (
            set /a "n=1000000+%%a" 
            set "data=%%b"
            setlocal enabledelayedexpansion
            set "data=!data:%findStr%=%replaceStr%!"
            echo !n!:!data!
            endlocal
        ) 
    )> "%tempFile%"

    rem Sort the output file to get the final file
    (for /f tokens^=^1^*^ delims^=^:^ eol^= %%a in ('sort "%tempFile%"') do (
        if "%%b"=="" ( 
            echo.
        ) else (
            echo %%b
        )
    )) > "%file%.repl"