Using while loops to count elements in a list

Question

places = [\"Jack\", \"John\", \"Sochi\"]
count=0
multi_word=0
place  = places[count]
while place != \"Sochi\" and count < len(places):
    if \' \' in place:
             


        

Answer 1

Why not try a more pythonic solution instead ?

places = ["Jack", "John", "Sochi"]

try:
    count = places.index("Sochi")
except ValueError:
    count = len(places)

multi_word = len([place for place in places[:count] if ' ' in place])