Spliting an hex into 2 hex values

Question

I have a problem I have an Hexadecimal like 0x6002 and I have to split it into 0x60 and 0x02. how do I do that?

I progam in cp

Answer 1

You can use masking to extract the low byte and a shift to extract the high byte:

uint16_t a = 0x6002;
uint8_t a0 = a & 0xff;  // a0 = 0x02
uint8_t a1 = a >> 8;    // a1 = 0x60

Note that the & 0xff is not strictly necessary for a narrowing unsigned conversion such as that above, but there are other cases where it might be necessary (e.g. when signed conversion is involved, or when the destination type is wider than 8 bits), so I'll leave it in for illustrative purposes.