Bash script that executes php file every 5 seconds

Question

Bash script:

$ cat test.sh
#!/bin/bash
while true
do
 /home/user/public_html/website.com/test.php
 sleep 5
done

Im trying to call it with c

Answer 1

An alternative answer is to run you scripts for 12 times only, and put it in crontab

#!/bin/bash
for loop in 1 2 3 4 5 6 7 8 9 0 1 2; do
  /home/user/public_html/website.com/test.php &
  sleep 5
done

-- OR --

#!/bin/bash
loop=0
while [ $loop -lt 12 ]; do
  /home/user/public_html/website.com/test.php &
  sleep 5
  loop=$(($loop+1))
done

--update--

If your goal is not to have more than one test.php, use this script: (Run it once only, do not putting it in the crontab):

#!/bin/bash

while true; do
    begin=`date +%s`
    /home/user/public_html/website.com/test.php
    end=`date +%s`
    if [ $(($end - $begin)) -lt 5 ]; then
        sleep $(($begin + 5 - $end))
    fi
done

Explanation: This script calls test.php, and wait for it to terminate (since it dose not have & in the end). Then it measure the time: if it's already passed 5 seconds, it call test.php right away. otherwise, it sleeps for the remaining time so that next test.php will be called at the next 5 seconds starting from the beginning of the previous test.php