I have 3 models: Question, Option, Rule
Question has_many options; Option needs a foreign key for question_id
Rule table consists of 3 foreign_keys:
Note: I have found this way to solve the problem.Kindness from China.
If you have RailsAdmin with you,you may notice that you can see all rules of one question as long as one field of both question fields(assumption_question_id,consequent_question_id) equals to id of the question.
I have done detailed test on this and found out that Rails always generates a condition "question_id = [current_id]" which make to_sql outputs
SELECT `rules`.* FROM `rules` WHERE `rules`.`question_id` = 170
And the reason that the following model
class Question < ActiveRecord::Base
has_many :options
# Notice ↓
has_many :rules, ->(question) { where("assumption_question_id = ? OR consequent_question_id = ?", question.id, question.id) }, class_name: 'Rule'
# Notice ↑
end
makes Question.take.rules.to_sql be like this
SELECT `rules`.* FROM `rules` WHERE `rules`.`question_id` = 170 AND (assumption_question_id = 170 OR consequent_question_id = 170)
Is that we have not yet get ride of the annoy question_id so no matter how we describe or condition properly, our condition follows that "AND".
Then,we need to get ride of it.How?
Click here and you will know how,Find sector 8.1,and you can see
Article.where(id: 10, trashed: false).unscope(where: :id)
# SELECT "articles".* FROM "articles" WHERE trashed = 0
Then lets do it:
class Question < ActiveRecord::Base
has_many :options
# Notice ↓
has_many :rules, ->(question) { unscope(where: :question_id).where("assumption_question_id = ? OR consequent_question_id = ?", question.id, question.id) }, class_name: 'Rule'
# Notice ↑
end
class Rule < ActiveRecord::Base
belongs_to :option
belongs_to :assumption_question, class_name: "Question", foreign_key: :assumption_question_id, inverse_of: :assumption_rules
belongs_to :consequent_question, class_name: "Question", foreign_key: :consequent_question_id, inverse_of: :consequent_rules
end
class Option < ActiveRecord::Base
belongs_to :question
has_one :rule
end
All done.
This is my first answer here at stackoverflow,and this method is never found anywhere else.
Thanks for reading.