Passing by reference does not change the variable

Question

I am trying to implement a function to change state of the menu, but my reference is lost when it leaves the function:

void gotoLowerlevel(Menu *item)
{
             


        

Answer 1

You're passing the pointer by value.

Operations on the object it points to will be visible to the outside, but the pointer itself is only a copy.

You might want to use a pointer to pointer.