c++ garbage values in vector of pointer

Question

When I do:

for(i=0; i

s

Answer 1

This is because the vector reallocated its internal storage when it grows beyond its current capacity; after the reallocation, the address of elements may have changed.

You can avoid reallocation by reserving a big enough storage beforehand:

vectorA.reserve(size);
//vectorB.reserve(size); // this would not hurt either
for(i=0; i

One final note: if you can use C++11, emplace_back constructs your object in place, hence, without copying.