How can I delete a specific child node in Firebase from UITableViewCell using Swift

Question

I have a UITableView which looks like this image

.

When I swipe to delete th

Answer 1

To solve this issue I tried a number of different methods before finally reaching my intended result.

To delete the value, I created a reference to the child node 'userExercises', then ordered it by 'exerciseName' and then .queryEqual(toValue:) the exercise name value which I extracted form the UITableViewCell.

I then removed the snapshot value of this and the example code is below:

func tableView(_ tableView: UITableView, commit editingStyle: UITableViewCellEditingStyle, forRowAt indexPath: IndexPath) {
    if editingStyle == .delete {

        if let exerciseName = exercises[indexPath.row].exerciseName {

            let ref = FIRDatabase.database().reference().child("userExercises")

            ref.queryOrdered(byChild: "exerciseName").queryEqual(toValue: exerciseName).observe(.childAdded, with: { (snapshot) in

                snapshot.ref.removeValue(completionBlock: { (error, reference) in
                    if error != nil {
                        print("There has been an error:\(error)")
                    }
                })

            })

        }

        exercises.remove(at: indexPath.row)
        tableView.deleteRows(at: [indexPath], with: .left)
    }
}