Return Table Type from A function in PostgreSQL

Question

I have a function from which has a return type as TABLE, and I want to get certain columns from my table into that RETURN TABLE type for my functionality. When I execute the

Answer 1

I was able to solve this issue by using a RETURN QUERY for the SELECT statement where I was using PERFORM. The below mentioned query helped me achieve my requirement.

CREATE OR REPLACE FUNCTION ccdb.fn_email_details_auto()
  RETURNS TABLE (code integer, area smallint, action smallint, flag smallint, ucount integer, view_cnt integer) AS
$BODY$

DECLARE 
sec_col refcursor;
cnt integer;
sec_code ccdb.update_qtable%ROWTYPE;

BEGIN

SELECT COUNT(DISTINCT section_code)
INTO cnt
FROM ccdb.update_qtable
WHERE entry_time::date = now()::date - interval '1 day';

OPEN sec_col FOR
SELECT DISTINCT ON (section_code)* FROM ccdb.update_qtable WHERE entry_time::date = now()::date - interval '1 day';

FOR i IN 1..cnt
LOOP

FETCH sec_col INTO sec_code;

RETURN QUERY 
SELECT section_code, ddu_area, ddu_action, status_flag, ccdb_ucount, ccdb_view_cnt
FROM ccdb.update_qtable
WHERE entry_time::date = now()::date - interval '1 day' AND section_code = sec_code.section_code
ORDER BY ddu_area, ddu_action;

END LOOP;

CLOSE sec_col;

END;
$BODY$
  LANGUAGE plpgsql VOLATILE
  COST 100;