Why am I getting a SyntaxError in the Python interpreter?

Question

This code works when I try it from a .py file, but fails in the command line interpreter and Idle.

>>> try:
...     fsock = open(\"/bla\")
... excep         


        

Answer 1

You need to leave a blank line to close the except block. The ... indicates it is still trying to put code in that block, even though you dedent it. This is just a quirk of the interactive interpreter.