Why this behavior happens?
long value = 123450;
System.out.println(\"value: \" + value);
value: 123450
long
Why this behavior happens?
Just as literals starting with 0x
are treated as hexadecimal numbers (base 16), literals starting with a 0
are treated as octal numbers, i.e., numbers in base 8.
(Try writing 0789, and you'll see that the compiler will complain.)
What is this 42792?
The number 123450 in base 8 represents the number
1×85 + 2×84 + 3×83 + 4×82 + 5×81 + 0×80 = 42792