Implementing B=f(A), with B and A arrays and B already defined

Question

Suppose I have an array B that has been already defined and used somewhere in a C++ code. Now, suppose that I have another array A that has been de

Answer 1

The easiest way it to use std::vector or std::array

example:

vector f(const vector& a) {
   return a;
}

b = f(a);

Actually, you don't have to use one of this classes to store, you may use your own class, that have operator =

YourClass& operator = (const vector&/* there will be returned value of f, it may be std::array, std::vector or your own class.*/ v) {
    //fill it here.
    return *this;
}

You may also provide move constructor for it to avoid unnecessary copying.

for example

class Array {
    int* data;   
    YourClass& operator = (YourClass&& v) {
        swap(v.data, data);
    }
}

YourClass f(const YourClass& a) {
   //
}

Array a,b;
b = f(a);