What is the reason for error while returning a structure in this C program?

Question

My program intends to achieve this

(A) Write a C function named larger() that returns the later date of any two dates passed to it. For

Answer 1

@Rüppell'sVulture You highlighted his errors but the code is too erroneous. I have worked on a simpler solution of it. Have a look.

@iMPose27 Please see the following code and let me know in case you run in some difficulty

// includes
#include 
#include 

// macros
#define NUM 2

// structure Definitions
struct Dates
{
       int month;
       int day;
       int year;
};

// typedefs
typedef struct Dates DATES;

// function declarations
DATES* larger(DATES[NUM]);

// function definitions
int main(int argc, char* argv[])
{
    DATES user[NUM];    // array of NUM DATES
    DATES *result=NULL;
    int i=0;
    printf("\nPlease Enter Two Dates, The program will evaluate and return the later date of the two dates passed to it\n\n");
    for(;i 12);

        do{
              printf("Please enter the day, 1-31:\t");
              scanf("%d", &user[i].day);
        }while (user[i].day < 1 || user[i].day > 31);

        do{           
              printf("Please enter the year: \t");
              scanf("%d)", &user[i].year);
        }while (user[i].year < 1);

        printf("\nDate %d entered: %d/%d/%d.\n\n", i+1, user[i].month, user[i].day, user[i].year);

    } 

    if((result=larger(user))==NULL)
        printf("The two dates passed, date1: %d/%d/%d and date2: %d/%d/%d are the same.\n",user[0].month, user[0].day, user[0].year, user[1].month, user[1].day, user[1].year); 
    else
        printf("%d/%d/%d is the later date of the two dates passed\n",result->month, result->day, result->year); 

    return 0;
}

DATES* larger(DATES more[NUM])
{        
      int days0, days1;

      days0 = (more[0].month*31)+(more[0].day)+(more[0].year*365);
      days1 = (more[1].month*31)+(more[1].day)+(more[1].year*365);

      if (days0 > days1)
        return more;        
      else if (days1 > days0)
        return more+1;
      else
        return 0;       
}