ORACLE - JSON To Key Value Pair Table

Question

Is there any way to obtain a table with key/value pairs from a CLOB Json Column?

The idea here is to get these values, on a dynamic way. Because the CLOB column does

Answer 1

Here's a variant that will walk a nested structure.

SQL> drop FUNCTION PROCESS_JSON_DOCUMENT
  2  /

Function dropped.

SQL> drop TYPE NV_PAIR_TABLE
  2  /

Type dropped.

SQL> drop TYPE NV_PAIR_T
  2  /

Type dropped.

SQL> create or replace TYPE NV_PAIR_T as object (
  2    JSON_PATH  VARCHAR2(4000),
  3    VALUE      VARCHAR2(4000)
  4  )
  5  /

Type created.

SQL> create or replace TYPE NV_PAIR_TABLE
  2  as TABLE of NV_PAIR_T
  3  /

Type created.

SQL> create or replace FUNCTION PROCESS_JSON_DOCUMENT(P_JSON_PATH VARCHAR2, P_JSON_DOCUMENT VARCHAR2)
  2  return NV_PAIR_TABLE PIPELINED
  3  as
  4    V_JSON_OBJECT    JSON_OBJECT_T := JSON_OBJECT_T(P_JSON_DOCUMENT);
  5    V_KEY_LIST       JSON_KEY_LIST := V_JSON_OBJECT.get_keys();
  6    V_KEY_NAME       VARCHAR2(4000);
  7    V_JSON_PATH      VARCHAR2(4000);
  8    V_CHILD_DOCUMENT VARCHAR2(4000);
  9  begin
 10    for i in 1..V_KEY_LIST.count loop
 11      V_KEY_NAME := V_KEY_LIST(i);
 12      if (V_JSON_OBJECT.get_type(V_KEY_LIST(i)) <> 'OBJECT') then
 13          pipe row (NV_PAIR_T(P_JSON_PATH || '.' || V_KEY_NAME,V_JSON_OBJECT.get_string(V_KEY_NAME)));
 14      else
 15        V_JSON_PATH := P_JSON_PATH || '.' || V_KEY_NAME;
 16        V_CHILD_DOCUMENT := V_JSON_OBJECT.get_object(V_KEY_NAME).to_string();
 17        for j in (select * from TABLE(PROCESS_JSON_DOCUMENT(V_JSON_PATH, V_CHILD_DOCUMENT))) loop
 18          pipe row (NV_PAIR_T(J.JSON_PATH,J.VALUE));
 19        end loop;
 20      end if;
 21    end loop;
 22  end;
 23  /

Function created.

SQL> column JSON_PATH format A32
SQL> column VALUE format A32
SQL> select *
  2   from TABLE(PROCESS_JSON_DOCUMENT('$','{"A":"AA", "B":"BB", "C":"CC", "X" : {"A":"AA", "B":"BB", "C":"CC"}}'))
  3  /
$.A                              AA
$.B                              BB
$.C                              CC
$.X.A                            AA
$.X.B                            BB
$.X.C                            CC

6 rows selected.

SQL>