The issue has to do with the scope of the array variable that you're returning in your method. Right now you're returning array, a local variable defined in the method, point. However, once point is finished executing, all local variables within the function frame, including array will be discarded from main memory. So even though you still get a memory address from point, there's no telling what could be at that memory address. Therefore, treating array as an int array when printing out its elements will lead to a segmentation fault.
My suggestion to fix this is to allocate memory from the heap using malloc so that array lasts outside the frame of point. The solution should look like this,
int* point(int a[])
{
printf("In the point function\n");
int *array = (int *) malloc(4 * sizeof(int)); //dynamically allocate memory for 4 integers
int i;
for(i=0;i<4;i++)
{
printf("%dth Iteration\n",i);
array[i]=a[i];
}
return array;
}
