Return multiple values over time

Question

Okay, so is there a way to return a value from a function - the way return does - but not stop the function - the way return does?

Answer 1

def f():
  for i in range(10):
     yield i

g = f().next

# this is if you actually want to get a function
# and then call it repeatedly to get different values
print g()
print g()

print

# this is how you might normally use a generator
for i in f():
  print i

Output:

0
1

0
1
...
9